2005 Problem of the Week Competition: Problems
Final
Results!!!
SJSU
Math Dept.
Fall
2005
Undergraduate
Division
1st
prize $50 Cuong Dong
2nd
prize $30 Andrew Macheret
3rd prize $20 Johan
Johansson
Graduate Division
1st
prize $50 Weidong Shao
2nd
prize $30 Matthew Low
3rd prize $20 Helene
Payne
SJMC
Division
1st
prize $50 Powell Akagawa
2nd
prize $30 Bowei Liu
Stop by the math office to make sure that we have your
correct student ID number. Your
checks can be picked up after Feb. 1.
Final
Week!!!
11/18/05
Week
#13 Mon. Nov. 21 Fri. Dec. 2
Problem
13 (25 points): The vertices of a
10-dimensional cube are represented by the set of 1024 binary sequences of
length 10 (each digit is either 0 or 1). Let
S be any subset of at least 205 binary sequences (vertices).
Show that S will always contain an equilateral triangle.
Copies
of this problem (and answers to the old problems) are available from the shelves
in front of the Math office, MH 308, or online at http://www.math.sjsu.edu/~jackson.
Solutions to problem #13 should be submitted to the Math office by Fri.
Dec. 2 at noon. Remember that a
correct solution should also contain an explanation of the answer.
Make sure that your name, student ID number, and the division you are
participating in (undergraduate or graduate or SJMC) are printed legibly at the
top of the page. The final results
of the POW competition and a correct solution to problem #13 will be posted on
Mon. Dec. 5.
11/2/05
Problem
#11 (15 points): A sequence (of real numbers) of length
is simply an
-tuple
. A subsequence of
of length
is an
-tuple of the form
for some integers
. Such a subsequence is monotone if either
or else
.
(1)
Show if
is a positive integer and
is a sequence of length
, then
has a monotone subsequence of
length
.
(2)
Show (by specific example) that if instead
has length
, it is possible that the longest monotone subsequence of
has length
.
(3)
For all positive integers
, let
be the largest integer
such that every sequence of length
has a monotone subsequence of
length
. Show that
for all
, where
denotes the ceiling function.
10/26/05
Week
#10 Wed. Oct. 26 Fri. Nov. 4
Problem
10 (14 points): Given any 4 real
numbers a,b,c,d satisfying a + b + c + d = 0, prove that the sum of their cubes
is equal to 0 (a3 + b3 + c3 + d3 =
0) if and only if the sum of their 5th powers is equal to 0 (a5
+ b5 + c5 + d5 = 0).
Problem
Of The Week, 10-24-2005
Problem
#9 (13 points)
For
each number
, find the limit;
.
10/12/05
Problem
8 (12 points):
There are 20 chairs around a circular table, numbered from 1 to 20, and
20 people have all been assigned different numbers from 1 to 20. When the people
take their seats, they dont have to sit at the chair with their number, but
they must be seated at most one place away from that chair. (For example, person
13 may sit in chair 12 or 13 or 14, and person 20 may sit in chair 19 or 20 or
1). How many seating arrangements are possible?
10/5/05
Week
#7 Wed. Oct. 5 Fri. Oct. 14
Problem
7 (11 points): Prove that there
exists an integer A such that for every pair of positive integers n,m such that
n,m > A, there is a tiling of an n x m rectangle using only 3 x 5 and 4 x 7
rectangles.
9/28/05
Problem of the Week
Problem #6 (10 points) for the week of October 3, 2005
A solid, call it S, is the region in three-dimensional space bounded by the planes
.
(a) Sketch one of the faces of S carefully using only a compass and a ruler. I like to see the traces of compass marks. Take two inches for the unit length. Indicate the length of each side. Find the area of the face, and the total surface area of S.
(b) Find the volume of S.
denote the sum of their areas. Next
form the convex hull of the construction so far by adding 3 new line segments
(shown as dotted lines), construct squares on these new segments (external to
the construction so far), call these the squares at level 2, and let
denote the sum of
their areas. Prove that the ratio
does not depend on
T
, and determine its value.
9/14/05
Week
#4 Wed. Sept. 14 Fri. Sept. 25
Problem
4 (8 points): Evaluate the limit as
n ฎ ฅ (find the exact value) of the sum
1/(2n+1)
+ 1/(2n+2) +
+ 1/(4n) .
Week
#3 Wed. Sept. 7 Fri. Sept. 16
Problem
3 (7 points): Let n
be a positive integer, and let p be a prime number.
Prove that
implies
.
Problem
2 (6 points): There were 5 married couples at a party. One man there asked
all 9 of the others there the following question: Before tonight, not counting
your spouse, how many of the people here had you met? Surprisingly, he received
9 different answers, no two of the answers he received were the same. What was
his wifes answer?
Week
#1 Wed. Aug. 24 Fri. Sept. 2
Problem
1 (5 points): How many 4-tuples of
positive integers {a,b,c,d} are there for which the lowest common multiple of
any three integers in the 4-tuple is 3n5m?